-4/(2x-2)^2

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Solution for -4/(2x-2)^2 equation: 


D( x )

(2*x-2)^2 = 0

(2*x-2)^2 = 0

(2*x-2)^2 = 0

2*x-2 = 0 // + 2

2*x = 2 // : 2

x = 2/2

x = 1

x in (-oo:1) U (1:+oo)

-4/((2*x-2)^2) = 0

-4 = 0

x belongs to the empty set

x belongs to the empty set

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